The pentagonal bipyramidal structure contains | vedclass

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(D) In a pentagonal bipyramidal geometry (e.g.,$IF_7$),there are two sets of positions: equatorial and axial.$1$. The five equatorial bonds are arrang

Vedclass · Accepted Answer

$72^o, 90^o, 180^o$

Vedclass · Answer

(D) In a pentagonal bipyramidal geometry (e.g.,$IF_7$),there are two sets of positions: equatorial and axial.$1$. The five equatorial bonds are arranged in a pentagon,resulting in bond angles of $360^o / 5 = 72^o$ between adjacent equatorial bonds.$2$. The two axial bonds are perpendicular to the equatorial plane,resulting in bond angles of $90^o$ between axial and equatorial bonds.$3$. The angle between the two axial bonds is $180^o$.Therefore,the bond angles present are $72^o, 90^o,$ and $180^o$.

List-$I$ (molecules/ions)	List-$II$ (No. of lone pairs of $e^-$ on central atom)
$A$. $IF_7$	$I$. Three
$B$. $ICl_4^-$	$II$. One
$C$. $XeF_6$	$III$. Two
$D$. $XeF_2$	$IV$. Zero

List-$I$ (Molecule)	List-$II$ (Shape)
$A. SF_4$	$I. T\text{-shaped}$
$B. ClF_3$	$II. \text{Square planar}$
$C. BrF_5$	$III. \text{See-saw}$
$D. XeF_4$	$IV. \text{Square pyramidal}$

The pentagonal bipyramidal structure contains bond angles of approximately:

Similar Questions

Group the following as linear and non-linear molecules: $H_2O$,$HOCl$,$BeCl_2$,$Cl_2O$.

Match List-$I$ with List-$II$.

List-$I$ (molecules/ions) List-$II$ (No. of lone pairs of $e^-$ on central atom)

$A$. $IF_7$ $I$. Three

$B$. $ICl_4^-$ $II$. One

$C$. $XeF_6$ $III$. Two

$D$. $XeF_2$ $IV$. Zero

Choose the correct answer from the options given below:

Which of the following molecules has trigonal planar geometry?

Match the molecules in List-$I$ with their respective shapes in List-$II$.
List-$I$ (Molecule) List-$II$ (Shape)
$A. SF_4$ $I. T\text{-shaped}$
$B. ClF_3$ $II. \text{Square planar}$
$C. BrF_5$ $III. \text{See-saw}$
$D. XeF_4$ $IV. \text{Square pyramidal}$

Which of the following statements is incorrect?

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